11-(t-3)+4t-3=t+5

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Solution for 11-(t-3)+4t-3=t+5 equation:



11-(t-3)+4t-3=t+5
We move all terms to the left:
11-(t-3)+4t-3-(t+5)=0
We add all the numbers together, and all the variables
4t-(t-3)-(t+5)+8=0
We get rid of parentheses
4t-t-t+3-5+8=0
We add all the numbers together, and all the variables
2t+6=0
We move all terms containing t to the left, all other terms to the right
2t=-6
t=-6/2
t=-3

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