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11+5x=60+(x-2)
We move all terms to the left:
11+5x-(60+(x-2))=0
We calculate terms in parentheses: -(60+(x-2)), so:We get rid of parentheses
60+(x-2)
determiningTheFunctionDomain (x-2)+60
We get rid of parentheses
x-2+60
We add all the numbers together, and all the variables
x+58
Back to the equation:
-(x+58)
5x-x-58+11=0
We add all the numbers together, and all the variables
4x-47=0
We move all terms containing x to the left, all other terms to the right
4x=47
x=47/4
x=11+3/4
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