11+2x=3x(x+2)

Solution for 11+2x=3x(x+2) equation:

11+2x=3x(x+2)

We move all terms to the left:

11+2x-(3x(x+2))=0


We calculate terms in parentheses: -(3x(x+2)), so:

3x(x+2)

We multiply parentheses

3x^2+6x

Back to the equation:

-(3x^2+6x)


We get rid of parentheses

-3x^2+2x-6x+11=0

We add all the numbers together, and all the variables

-3x^2-4x+11=0

a = -3; b = -4; c = +11;
Δ = b2-4ac
Δ = -42-4·(-3)·11
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{37}}{2*-3}=\frac{4-2\sqrt{37}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{37}}{2*-3}=\frac{4+2\sqrt{37}}{-6}
$