11+-1(3x+1)=7(x+-6)+2

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Solution for 11+-1(3x+1)=7(x+-6)+2 equation: 



11+-1(3x+1)=7(x+-6)+2

We move all terms to the left:

11+-1(3x+1)-(7(x+-6)+2)=0

We add all the numbers together, and all the variables

-1(3x+1)-(7(x-6)+2)+11+=0

We add all the numbers together, and all the variables

-1(3x+1)-(7(x-6)+2)=0



We calculate terms in parentheses: -(7(x-6)+2), so:

7(x-6)+2

We multiply parentheses

7x-42+2

We add all the numbers together, and all the variables

7x-40

Back to the equation:

-(7x-40)



We get rid of parentheses

-1(3x+1)-7x+40=0

We add all the numbers together, and all the variables

-7x-1(3x+1)+40=0

We move all terms containing x to the left, all other terms to the right

-7x-1(3x+1)=-40

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