11+(20-7)x2-34/9=

Solution for 11+(20-7)x2-34/9= equation:

11+(20-7)x2-34/9=

We move all terms to the left:

11+(20-7)x2-34/9-()=0

We add all the numbers together, and all the variables

13x2+11-34/9-()=0

We add all the numbers together, and all the variables

13x^2-34/9=0

We multiply all the terms by the denominator


13x^2*9-34=0

Wy multiply elements

117x^2-34=0

a = 117; b = 0; c = -34;
Δ = b2-4ac
Δ = 02-4·117·(-34)
Δ = 15912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15912}=\sqrt{36*442}=\sqrt{36}*\sqrt{442}=6\sqrt{442}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{442}}{2*117}=\frac{0-6\sqrt{442}}{234}
=-\frac{6\sqrt{442}}{234}
=-\frac{\sqrt{442}}{39}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{442}}{2*117}=\frac{0+6\sqrt{442}}{234}
=\frac{6\sqrt{442}}{234}
=\frac{\sqrt{442}}{39}
$