11+(-14/5)x=7

Solution for 11+(-14/5)x=7 equation:

11+(-14/5)x=7

We move all terms to the left:

11+(-14/5)x-(7)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(-14/5)x+4=0

We multiply parentheses

-14x^2+4=0

a = -14; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-14)·4
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{14}}{2*-14}=\frac{0-4\sqrt{14}}{-28}
=-\frac{4\sqrt{14}}{-28}
=-\frac{\sqrt{14}}{-7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{14}}{2*-14}=\frac{0+4\sqrt{14}}{-28}
=\frac{4\sqrt{14}}{-28}
=\frac{\sqrt{14}}{-7}
$