11(z+2)-4(z-4)=2(z-1)+4(z-3)

Solution for 11(z+2)-4(z-4)=2(z-1)+4(z-3) equation:

Simplifying
11(z + 2) + -4(z + -4) = 2(z + -1) + 4(z + -3)

Reorder the terms:
11(2 + z) + -4(z + -4) = 2(z + -1) + 4(z + -3)
(2 * 11 + z * 11) + -4(z + -4) = 2(z + -1) + 4(z + -3)
(22 + 11z) + -4(z + -4) = 2(z + -1) + 4(z + -3)

Reorder the terms:
22 + 11z + -4(-4 + z) = 2(z + -1) + 4(z + -3)
22 + 11z + (-4 * -4 + z * -4) = 2(z + -1) + 4(z + -3)
22 + 11z + (16 + -4z) = 2(z + -1) + 4(z + -3)

Reorder the terms:
22 + 16 + 11z + -4z = 2(z + -1) + 4(z + -3)

Combine like terms: 22 + 16 = 38
38 + 11z + -4z = 2(z + -1) + 4(z + -3)

Combine like terms: 11z + -4z = 7z
38 + 7z = 2(z + -1) + 4(z + -3)

Reorder the terms:
38 + 7z = 2(-1 + z) + 4(z + -3)
38 + 7z = (-1 * 2 + z * 2) + 4(z + -3)
38 + 7z = (-2 + 2z) + 4(z + -3)

Reorder the terms:
38 + 7z = -2 + 2z + 4(-3 + z)
38 + 7z = -2 + 2z + (-3 * 4 + z * 4)
38 + 7z = -2 + 2z + (-12 + 4z)

Reorder the terms:
38 + 7z = -2 + -12 + 2z + 4z

Combine like terms: -2 + -12 = -14
38 + 7z = -14 + 2z + 4z

Combine like terms: 2z + 4z = 6z
38 + 7z = -14 + 6z

Solving
38 + 7z = -14 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
38 + 7z + -6z = -14 + 6z + -6z

Combine like terms: 7z + -6z = 1z
38 + 1z = -14 + 6z + -6z

Combine like terms: 6z + -6z = 0
38 + 1z = -14 + 0
38 + 1z = -14

Add '-38' to each side of the equation.
38 + -38 + 1z = -14 + -38

Combine like terms: 38 + -38 = 0
0 + 1z = -14 + -38
1z = -14 + -38

Combine like terms: -14 + -38 = -52
1z = -52

Divide each side by '1'.
z = -52

Simplifying
z = -52