11(z+2)-4(z-1)=4(z-3)+2(z-4)

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Solution for 11(z+2)-4(z-1)=4(z-3)+2(z-4) equation:


11(z+2)-4(z-1)=4(z-3)+2(z-4)

We simplify the equation to the form, which is simple to understand
11(z+2)-4(z-1)=4(z-3)+2(z-4)

Reorder the terms in parentheses
+(+11z+22)-4*(z-1)=4*(z-3)+2*(z-4)

Remove unnecessary parentheses
+11z+22-4+*(+z-1+)=+4+*(+z-3+)+2+*(+z-4+)

Reorder the terms in parentheses
+11z+22+(-4z+4)=4*(z-3)+2*(z-4)

Remove unnecessary parentheses
+11z+22-4z+4=+4+*(+z-3+)+2+*(+z-4+)

Reorder the terms in parentheses
+11z+22-4z+4=+(+4z-12)+2*(z-4)

Remove unnecessary parentheses
+11z+22-4z+4=+4z-12+2+*(+z-4+)

Reorder the terms in parentheses
+11z+22-4z+4=+4z-12+(+2z-8)

Remove unnecessary parentheses
+11z+22-4z+4=+4z-12+2z-8

We move all terms containing z to the left and all other terms to the right.
+11z-4z-4z-2z=-12-8-22-4

We simplify left and right side of the equation.
+1z=-46

We divide both sides of the equation by 1 to get z.
z=-46

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