11(z+2)-2(z-2)=3(z-1)+5(z-1)

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Solution for 11(z+2)-2(z-2)=3(z-1)+5(z-1) equation: 



11(z+2)-2(z-2)=3(z-1)+5(z-1)

We move all terms to the left:

11(z+2)-2(z-2)-(3(z-1)+5(z-1))=0

We multiply parentheses

11z-2z-(3(z-1)+5(z-1))+22+4=0



We calculate terms in parentheses: -(3(z-1)+5(z-1)), so:

3(z-1)+5(z-1)

We multiply parentheses

3z+5z-3-5

We add all the numbers together, and all the variables

8z-8

Back to the equation:

-(8z-8)



We add all the numbers together, and all the variables

9z-(8z-8)+26=0

We get rid of parentheses

9z-8z+8+26=0

We add all the numbers together, and all the variables

z+34=0

We move all terms containing z to the left, all other terms to the right

z=-34

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