11(z+1)-4=4(z-1)+2(z-4)

Solution for 11(z+1)-4=4(z-1)+2(z-4) equation:

11(z+1)-4=4(z-1)+2(z-4)

We move all terms to the left:

11(z+1)-4-(4(z-1)+2(z-4))=0

We multiply parentheses

11z-(4(z-1)+2(z-4))+11-4=0


We calculate terms in parentheses: -(4(z-1)+2(z-4)), so:

4(z-1)+2(z-4)

We multiply parentheses

4z+2z-4-8

We add all the numbers together, and all the variables

6z-12

Back to the equation:

-(6z-12)


We add all the numbers together, and all the variables

11z-(6z-12)+7=0

We get rid of parentheses

11z-6z+12+7=0

We add all the numbers together, and all the variables

5z+19=0

We move all terms containing z to the left, all other terms to the right

5z=-19

z=-19/5

z=-3+4/5