11(z+1)-2(z-1)=4(z-2)+4(z-1)

Solution for 11(z+1)-2(z-1)=4(z-2)+4(z-1) equation:

11(z+1)-2(z-1)=4(z-2)+4(z-1)

We move all terms to the left:

11(z+1)-2(z-1)-(4(z-2)+4(z-1))=0

We multiply parentheses

11z-2z-(4(z-2)+4(z-1))+11+2=0


We calculate terms in parentheses: -(4(z-2)+4(z-1)), so:

4(z-2)+4(z-1)

We multiply parentheses

4z+4z-8-4

We add all the numbers together, and all the variables

8z-12

Back to the equation:

-(8z-12)


We add all the numbers together, and all the variables

9z-(8z-12)+13=0

We get rid of parentheses

9z-8z+12+13=0

We add all the numbers together, and all the variables

z+25=0

We move all terms containing z to the left, all other terms to the right

z=-25