11(y+1)=5(y-11)+36

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Solution for 11(y+1)=5(y-11)+36 equation: 



11(y+1)=5(y-11)+36

We move all terms to the left:

11(y+1)-(5(y-11)+36)=0

We multiply parentheses

11y-(5(y-11)+36)+11=0



We calculate terms in parentheses: -(5(y-11)+36), so:

5(y-11)+36

We multiply parentheses

5y-55+36

We add all the numbers together, and all the variables

5y-19

Back to the equation:

-(5y-19)



We get rid of parentheses

11y-5y+19+11=0

We add all the numbers together, and all the variables

6y+30=0

We move all terms containing y to the left, all other terms to the right

6y=-30

y=-30/6

y=-5

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