11(x-6)-12(x-2)=12x+6(x+12)

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Solution for 11(x-6)-12(x-2)=12x+6(x+12) equation: 



11(x-6)-12(x-2)=12x+6(x+12)

We move all terms to the left:

11(x-6)-12(x-2)-(12x+6(x+12))=0

We multiply parentheses

11x-12x-(12x+6(x+12))-66+24=0



We calculate terms in parentheses: -(12x+6(x+12)), so:

12x+6(x+12)

We multiply parentheses

12x+6x+72

We add all the numbers together, and all the variables

18x+72

Back to the equation:

-(18x+72)



We add all the numbers together, and all the variables

-1x-(18x+72)-42=0

We get rid of parentheses

-1x-18x-72-42=0

We add all the numbers together, and all the variables

-19x-114=0

We move all terms containing x to the left, all other terms to the right

-19x=114

x=114/-19

x=-6

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