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11(x+3)=2(3x-1)
We move all terms to the left:
11(x+3)-(2(3x-1))=0
We multiply parentheses
11x-(2(3x-1))+33=0
We calculate terms in parentheses: -(2(3x-1)), so:We get rid of parentheses
2(3x-1)
We multiply parentheses
6x-2
Back to the equation:
-(6x-2)
11x-6x+2+33=0
We add all the numbers together, and all the variables
5x+35=0
We move all terms containing x to the left, all other terms to the right
5x=-35
x=-35/5
x=-7
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