11(w-3)=10(w-4)+w+7

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Solution for 11(w-3)=10(w-4)+w+7 equation: 



11(w-3)=10(w-4)+w+7

We move all terms to the left:

11(w-3)-(10(w-4)+w+7)=0

We multiply parentheses

11w-(10(w-4)+w+7)-33=0



We calculate terms in parentheses: -(10(w-4)+w+7), so:

10(w-4)+w+7

We add all the numbers together, and all the variables

w+10(w-4)+7

We multiply parentheses

w+10w-40+7

We add all the numbers together, and all the variables

11w-33

Back to the equation:

-(11w-33)



We get rid of parentheses

11w-11w+33-33=0

We add all the numbers together, and all the variables

=0

w=0/1

w=0

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