11(t-4)+3t=7(2t+2)-10

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Solution for 11(t-4)+3t=7(2t+2)-10 equation: 


Simplifying
11(t + -4) + 3t = 7(2t + 2) + -10

Reorder the terms:
11(-4 + t) + 3t = 7(2t + 2) + -10
(-4 * 11 + t * 11) + 3t = 7(2t + 2) + -10
(-44 + 11t) + 3t = 7(2t + 2) + -10

Combine like terms: 11t + 3t = 14t
-44 + 14t = 7(2t + 2) + -10

Reorder the terms:
-44 + 14t = 7(2 + 2t) + -10
-44 + 14t = (2 * 7 + 2t * 7) + -10
-44 + 14t = (14 + 14t) + -10

Reorder the terms:
-44 + 14t = 14 + -10 + 14t

Combine like terms: 14 + -10 = 4
-44 + 14t = 4 + 14t

Add '-14t' to each side of the equation.
-44 + 14t + -14t = 4 + 14t + -14t

Combine like terms: 14t + -14t = 0
-44 + 0 = 4 + 14t + -14t
-44 = 4 + 14t + -14t

Combine like terms: 14t + -14t = 0
-44 = 4 + 0
-44 = 4

Solving
-44 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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