11(n+2)+6=3n-4

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Solution for 11(n+2)+6=3n-4 equation:


Simplifying
11(n + 2) + 6 = 3n + -4

Reorder the terms:
11(2 + n) + 6 = 3n + -4
(2 * 11 + n * 11) + 6 = 3n + -4
(22 + 11n) + 6 = 3n + -4

Reorder the terms:
22 + 6 + 11n = 3n + -4

Combine like terms: 22 + 6 = 28
28 + 11n = 3n + -4

Reorder the terms:
28 + 11n = -4 + 3n

Solving
28 + 11n = -4 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
28 + 11n + -3n = -4 + 3n + -3n

Combine like terms: 11n + -3n = 8n
28 + 8n = -4 + 3n + -3n

Combine like terms: 3n + -3n = 0
28 + 8n = -4 + 0
28 + 8n = -4

Add '-28' to each side of the equation.
28 + -28 + 8n = -4 + -28

Combine like terms: 28 + -28 = 0
0 + 8n = -4 + -28
8n = -4 + -28

Combine like terms: -4 + -28 = -32
8n = -32

Divide each side by '8'.
n = -4

Simplifying
n = -4

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