11(n+1)+35=3n

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Solution for 11(n+1)+35=3n equation: 



11(n+1)+35=3n

We move all terms to the left:

11(n+1)+35-(3n)=0

We add all the numbers together, and all the variables

-3n+11(n+1)+35=0

We multiply parentheses

-3n+11n+11+35=0

We add all the numbers together, and all the variables

8n+46=0

We move all terms containing n to the left, all other terms to the right

8n=-46

n=-46/8

n=-5+3/4

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