11(m+12)=2(2-2m)-m

Solution for 11(m+12)=2(2-2m)-m equation:

11(m+12)=2(2-2m)-m

We move all terms to the left:

11(m+12)-(2(2-2m)-m)=0

We add all the numbers together, and all the variables

11(m+12)-(2(-2m+2)-m)=0

We multiply parentheses

11m-(2(-2m+2)-m)+132=0


We calculate terms in parentheses: -(2(-2m+2)-m), so:

2(-2m+2)-m

We add all the numbers together, and all the variables

-1m+2(-2m+2)

We multiply parentheses

-1m-4m+4

We add all the numbers together, and all the variables

-5m+4

Back to the equation:

-(-5m+4)


We get rid of parentheses

11m+5m-4+132=0

We add all the numbers together, and all the variables

16m+128=0

We move all terms containing m to the left, all other terms to the right

16m=-128

m=-128/16

m=-8