11(c-2)+6=3+c-19

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Solution for 11(c-2)+6=3+c-19 equation: 


Simplifying
11(c + -2) + 6 = 3 + c + -19

Reorder the terms:
11(-2 + c) + 6 = 3 + c + -19
(-2 * 11 + c * 11) + 6 = 3 + c + -19
(-22 + 11c) + 6 = 3 + c + -19

Reorder the terms:
-22 + 6 + 11c = 3 + c + -19

Combine like terms: -22 + 6 = -16
-16 + 11c = 3 + c + -19

Reorder the terms:
-16 + 11c = 3 + -19 + c

Combine like terms: 3 + -19 = -16
-16 + 11c = -16 + c

Add '16' to each side of the equation.
-16 + 16 + 11c = -16 + 16 + c

Combine like terms: -16 + 16 = 0
0 + 11c = -16 + 16 + c
11c = -16 + 16 + c

Combine like terms: -16 + 16 = 0
11c = 0 + c
11c = c

Solving
11c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
11c + -1c = c + -1c

Combine like terms: 11c + -1c = 10c
10c = c + -1c

Combine like terms: c + -1c = 0
10c = 0

Divide each side by '10'.
c = 0.0

Simplifying
c = 0.0

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