11(a-4)+a=3(2a+7)+7

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Solution for 11(a-4)+a=3(2a+7)+7 equation: 



11(a-4)+a=3(2a+7)+7

We move all terms to the left:

11(a-4)+a-(3(2a+7)+7)=0

We add all the numbers together, and all the variables

a+11(a-4)-(3(2a+7)+7)=0

We multiply parentheses

a+11a-(3(2a+7)+7)-44=0



We calculate terms in parentheses: -(3(2a+7)+7), so:

3(2a+7)+7

We multiply parentheses

6a+21+7

We add all the numbers together, and all the variables

6a+28

Back to the equation:

-(6a+28)



We add all the numbers together, and all the variables

12a-(6a+28)-44=0

We get rid of parentheses

12a-6a-28-44=0

We add all the numbers together, and all the variables

6a-72=0

We move all terms containing a to the left, all other terms to the right

6a=72

a=72/6

a=12

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