11(8c+5)-8c=2(40c+25)+5

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Solution for 11(8c+5)-8c=2(40c+25)+5 equation: 



11(8c+5)-8c=2(40c+25)+5

We move all terms to the left:

11(8c+5)-8c-(2(40c+25)+5)=0

We add all the numbers together, and all the variables

-8c+11(8c+5)-(2(40c+25)+5)=0

We multiply parentheses

-8c+88c-(2(40c+25)+5)+55=0



We calculate terms in parentheses: -(2(40c+25)+5), so:

2(40c+25)+5

We multiply parentheses

80c+50+5

We add all the numbers together, and all the variables

80c+55

Back to the equation:

-(80c+55)



We add all the numbers together, and all the variables

80c-(80c+55)+55=0

We get rid of parentheses

80c-80c-55+55=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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