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11(5x+8)55x+88=
We move all terms to the left:
11(5x+8)55x+88-()=0
We add all the numbers together, and all the variables
11(5x+8)55x=0
We multiply parentheses
3025x^2+4840x=0
a = 3025; b = 4840; c = 0;
Δ = b2-4ac
Δ = 48402-4·3025·0
Δ = 23425600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23425600}=4840$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4840)-4840}{2*3025}=\frac{-9680}{6050} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4840)+4840}{2*3025}=\frac{0}{6050} =0 $
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