11(3-x)=10(3x-2)

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Solution for 11(3-x)=10(3x-2) equation: 



11(3-x)=10(3x-2)

We move all terms to the left:

11(3-x)-(10(3x-2))=0

We add all the numbers together, and all the variables

11(-1x+3)-(10(3x-2))=0

We multiply parentheses

-11x-(10(3x-2))+33=0



We calculate terms in parentheses: -(10(3x-2)), so:

10(3x-2)

We multiply parentheses

30x-20

Back to the equation:

-(30x-20)



We get rid of parentheses

-11x-30x+20+33=0

We add all the numbers together, and all the variables

-41x+53=0

We move all terms containing x to the left, all other terms to the right

-41x=-53

x=-53/-41

x=1+12/41

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