11(2x-3)=5(2x+2)=5

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Solution for 11(2x-3)=5(2x+2)=5 equation: 



11(2x-3)=5(2x+2)=5

We move all terms to the left:

11(2x-3)-(5(2x+2))=0

We multiply parentheses

22x-(5(2x+2))-33=0



We calculate terms in parentheses: -(5(2x+2)), so:

5(2x+2)

We multiply parentheses

10x+10

Back to the equation:

-(10x+10)



We get rid of parentheses

22x-10x-10-33=0

We add all the numbers together, and all the variables

12x-43=0

We move all terms containing x to the left, all other terms to the right

12x=43

x=43/12

x=3+7/12

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