10z-3y-(-2z)+2y=12z-y

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Solution for 10z-3y-(-2z)+2y=12z-y equation:


Simplifying
10z + -3y + -1(-2z) + 2y = 12z + -1y

Remove parenthesis around (-2z)
10z + -3y + -1 * -2z + 2y = 12z + -1y

Multiply -1 * -2
10z + -3y + 2z + 2y = 12z + -1y

Reorder the terms:
-3y + 2y + 10z + 2z = 12z + -1y

Combine like terms: -3y + 2y = -1y
-1y + 10z + 2z = 12z + -1y

Combine like terms: 10z + 2z = 12z
-1y + 12z = 12z + -1y

Reorder the terms:
-1y + 12z = -1y + 12z

Add 'y' to each side of the equation.
-1y + y + 12z = -1y + y + 12z

Combine like terms: -1y + y = 0
0 + 12z = -1y + y + 12z
12z = -1y + y + 12z

Combine like terms: -1y + y = 0
12z = 0 + 12z
12z = 12z

Add '-12z' to each side of the equation.
12z + -12z = 12z + -12z

Combine like terms: 12z + -12z = 0
0 = 12z + -12z

Combine like terms: 12z + -12z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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