10z-30=6(z-5)B

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Solution for 10z-30=6(z-5)B equation: 



10z-30=6(z-5)

We move all terms to the left:

10z-30-(6(z-5))=0



We calculate terms in parentheses: -(6(z-5)), so:

6(z-5)

We multiply parentheses

6z-30

Back to the equation:

-(6z-30)



We get rid of parentheses

10z-6z+30-30=0

We add all the numbers together, and all the variables

4z=0

z=0/4

z=0

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