10z+4z-2z+6=48

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Solution for 10z+4z-2z+6=48 equation: 



10z+4z-2z+6=48

We move all terms to the left:

10z+4z-2z+6-(48)=0

We add all the numbers together, and all the variables

12z-42=0

We move all terms containing z to the left, all other terms to the right

12z=42

z=42/12

z=3+1/2

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