10z+40-3z-6=2z-4+4z-4

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Solution for 10z+40-3z-6=2z-4+4z-4 equation: 



10z+40-3z-6=2z-4+4z-4

We move all terms to the left:

10z+40-3z-6-(2z-4+4z-4)=0

We add all the numbers together, and all the variables

10z-3z-(6z-8)+40-6=0

We add all the numbers together, and all the variables

7z-(6z-8)+34=0

We get rid of parentheses

7z-6z+8+34=0

We add all the numbers together, and all the variables

z+42=0

We move all terms containing z to the left, all other terms to the right

z=-42

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