10y2-17y+12=y+16

Solution for 10y2-17y+12=y+16 equation:

10y^2-17y+12=y+16

We move all terms to the left:

10y^2-17y+12-(y+16)=0

We get rid of parentheses

10y^2-17y-y-16+12=0

We add all the numbers together, and all the variables

10y^2-18y-4=0

a = 10; b = -18; c = -4;
Δ = b2-4ac
Δ = -182-4·10·(-4)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-22}{2*10}=\frac{-4}{20}
=-1/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+22}{2*10}=\frac{40}{20}
=2
$