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10y^2+9y-7=0
a = 10; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·10·(-7)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-19}{2*10}=\frac{-28}{20} =-1+2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+19}{2*10}=\frac{10}{20} =1/2 $
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