10y-5*(1+y)=3*(2y-2)-20

Simple and best practice solution for 10y-5*(1+y)=3*(2y-2)-20 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 10y-5*(1+y)=3*(2y-2)-20 equation: 



10y-5(1+y)=3(2y-2)-20

We move all terms to the left:

10y-5(1+y)-(3(2y-2)-20)=0

We add all the numbers together, and all the variables

10y-5(y+1)-(3(2y-2)-20)=0

We multiply parentheses

10y-5y-(3(2y-2)-20)-5=0



We calculate terms in parentheses: -(3(2y-2)-20), so:

3(2y-2)-20

We multiply parentheses

6y-6-20

We add all the numbers together, and all the variables

6y-26

Back to the equation:

-(6y-26)



We add all the numbers together, and all the variables

5y-(6y-26)-5=0

We get rid of parentheses

5y-6y+26-5=0

We add all the numbers together, and all the variables

-1y+21=0

We move all terms containing y to the left, all other terms to the right

-y=-21

y=-21/-1

y=+21

See similar equations:

| 4(3x-5)=10 | | N/7-9n/14=-1/7 | | 8=x/3+12 | | 8x=12+2x-1+x | | 0.6x+1.6=0.9x-0.8 | | j+6=12+6 | | 29x-58=406 | | 2(5x+4)=3+8x-15 | | (2x+5)+5=14 | | 7(2c-1)-(1=6+6c | | 6=n+(-9) | | 7x+3(23+140x)=3.19 | | (6x−5)^2​​=(4x−3)^​2​​+4 | | (6x−5)​2​​=(4x−3)​2​​+4 | | 10+9+d=210 | | 16=3x=8 | | 7x+9=x+4 | | 91=-7(2n-5) | | 3b+15=5b–21 | | 8+x-3=11 | | 2+-t=-1 | | 2j+j+j+6=54 | | 10.9=x–2.8 | | b/11-9b/11=16/12 | | 30b+10=-20 | | -1+3f=7-6f | | 8=-8k | | (6a-54)-(-5a+-27)=23 | | -16(11+x)=-416 | | 1/3x-4=4/9 | | C=25+7h=81 | | 6t-5=9t-9 |

Equations solver categories