10y-(4y+3)=63

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Solution for 10y-(4y+3)=63 equation: 



10y-(4y+3)=63

We move all terms to the left:

10y-(4y+3)-(63)=0

We get rid of parentheses

10y-4y-3-63=0

We add all the numbers together, and all the variables

6y-66=0

We move all terms containing y to the left, all other terms to the right

6y=66

y=66/6

y=11

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