10y+4-2y=2-2(y-4)

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Solution for 10y+4-2y=2-2(y-4) equation: 



10y+4-2y=2-2(y-4)

We move all terms to the left:

10y+4-2y-(2-2(y-4))=0

We add all the numbers together, and all the variables

8y-(2-2(y-4))+4=0



We calculate terms in parentheses: -(2-2(y-4)), so:

2-2(y-4)

determiningTheFunctionDomain
-2(y-4)+2

We multiply parentheses

-2y+8+2

We add all the numbers together, and all the variables

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

8y+2y-10+4=0

We add all the numbers together, and all the variables

10y-6=0

We move all terms containing y to the left, all other terms to the right

10y=6

y=6/10

y=3/5

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