10x=4(4x-3)=4(6x+4)=4

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Solution for 10x=4(4x-3)=4(6x+4)=4 equation: 



10x=4(4x-3)=4(6x+4)=4

We move all terms to the left:

10x-(4(4x-3))=0



We calculate terms in parentheses: -(4(4x-3)), so:

4(4x-3)

We multiply parentheses

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

10x-16x+12=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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