10x2-80x=-150

Solution for 10x2-80x=-150 equation:

10x^2-80x=-150

We move all terms to the left:

10x^2-80x-(-150)=0

We add all the numbers together, and all the variables

10x^2-80x+150=0

a = 10; b = -80; c = +150;
Δ = b2-4ac
Δ = -802-4·10·150
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-20}{2*10}=\frac{60}{20}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+20}{2*10}=\frac{100}{20}
=5
$