10x2-49x-33=0

Solution for 10x2-49x-33=0 equation:

10x^2-49x-33=0

a = 10; b = -49; c = -33;
Δ = b2-4ac
Δ = -492-4·10·(-33)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-61}{2*10}=\frac{-12}{20}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+61}{2*10}=\frac{110}{20}
=5+1/2
$