10x2-48=-74x

Solution for 10x2-48=-74x equation:

10x^2-48=-74x

We move all terms to the left:

10x^2-48-(-74x)=0

We get rid of parentheses

10x^2+74x-48=0

a = 10; b = 74; c = -48;
Δ = b2-4ac
Δ = 742-4·10·(-48)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-86}{2*10}=\frac{-160}{20}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+86}{2*10}=\frac{12}{20}
=3/5
$