10x2+59x+63=0

Solution for 10x2+59x+63=0 equation:

10x^2+59x+63=0

a = 10; b = 59; c = +63;
Δ = b2-4ac
Δ = 592-4·10·63
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-31}{2*10}=\frac{-90}{20}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+31}{2*10}=\frac{-28}{20}
=-1+2/5
$