10x2+4x=32

Solution for 10x2+4x=32 equation:

10x^2+4x=32

We move all terms to the left:

10x^2+4x-(32)=0

a = 10; b = 4; c = -32;
Δ = b2-4ac
Δ = 42-4·10·(-32)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-36}{2*10}=\frac{-40}{20}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+36}{2*10}=\frac{32}{20}
=1+3/5
$