10x2+25x=15

Solution for 10x2+25x=15 equation:

10x^2+25x=15

We move all terms to the left:

10x^2+25x-(15)=0

a = 10; b = 25; c = -15;
Δ = b2-4ac
Δ = 252-4·10·(-15)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-35}{2*10}=\frac{-60}{20}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+35}{2*10}=\frac{10}{20}
=1/2
$