10x2+24x+15=1

Solution for 10x2+24x+15=1 equation:

10x^2+24x+15=1

We move all terms to the left:

10x^2+24x+15-(1)=0

We add all the numbers together, and all the variables

10x^2+24x+14=0

a = 10; b = 24; c = +14;
Δ = b2-4ac
Δ = 242-4·10·14
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4}{2*10}=\frac{-28}{20}
=-1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4}{2*10}=\frac{-20}{20}
=-1
$