If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2+20x+9=0
a = 10; b = 20; c = +9;
Δ = b2-4ac
Δ = 202-4·10·9
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{10}}{2*10}=\frac{-20-2\sqrt{10}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{10}}{2*10}=\frac{-20+2\sqrt{10}}{20} $
| 12x+30(x+2)=144 | | 1+5y+3+5+2y+5=49⇒5y+2y+1+3+5+5=49⇒7y+14=49⇒7y=49-14⇒7y=35⇒y=357⇒y= | | 1/2-2=2x-1/2 | | 9h2+6h+1=0 | | 3x-54=126 | | -5w+27=17 | | 3x+54=126 | | 20.4=-15.5+(-3.6x)+1.8X | | 16=19-3+4x | | 20.5=-15.5+(-36x)+1.8 | | 2-11/p=11 | | 2t+4Y=7 | | 60+4(x-1)=90 | | 60-4(x-1)=90 | | F(-17)=-3x+1 | | 60-4x-4=90 | | t=16^2+96t | | 16=4p–16 | | 2x÷4=8 | | 6+t/2=5 | | 200x+100=400x | | 68=2+6x | | (10-2)x3+5=29 | | 6r-12=30 | | 2^x☓3^x=216 | | 12x-10=45 | | 1x+20=30x | | 17-(5n/4=) | | 7/24=x/8+1/6 | | (7/6)x=35 | | 200x+160=199 | | 1/3x+13=10 |