10x-x2=20,16

Solution for 10x-x2=20,16 equation:

10x-x2=20.16

We move all terms to the left:

10x-x2-(20.16)=0

We add all the numbers together, and all the variables

-1x^2+10x-20.16=0

a = -1; b = 10; c = -20.16;
Δ = b2-4ac
Δ = 102-4·(-1)·(-20.16)
Δ = 19.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{19.36}}{2*-1}=\frac{-10-\sqrt{19.36}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{19.36}}{2*-1}=\frac{-10+\sqrt{19.36}}{-2}
$