10x-7(2x-3)=65

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Solution for 10x-7(2x-3)=65 equation: 



10x-7(2x-3)=65

We move all terms to the left:

10x-7(2x-3)-(65)=0

We multiply parentheses

10x-14x+21-65=0

We add all the numbers together, and all the variables

-4x-44=0

We move all terms containing x to the left, all other terms to the right

-4x=44

x=44/-4

x=-11

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