10x-5(x-4)=20+7(x+4)

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Solution for 10x-5(x-4)=20+7(x+4) equation: 



10x-5(x-4)=20+7(x+4)

We move all terms to the left:

10x-5(x-4)-(20+7(x+4))=0

We multiply parentheses

10x-5x-(20+7(x+4))+20=0



We calculate terms in parentheses: -(20+7(x+4)), so:

20+7(x+4)

determiningTheFunctionDomain
7(x+4)+20

We multiply parentheses

7x+28+20

We add all the numbers together, and all the variables

7x+48

Back to the equation:

-(7x+48)



We add all the numbers together, and all the variables

5x-(7x+48)+20=0

We get rid of parentheses

5x-7x-48+20=0

We add all the numbers together, and all the variables

-2x-28=0

We move all terms containing x to the left, all other terms to the right

-2x=28

x=28/-2

x=-14

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