10x-4(x-2)=5(2x+1)+5

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Solution for 10x-4(x-2)=5(2x+1)+5 equation: 



10x-4(x-2)=5(2x+1)+5

We move all terms to the left:

10x-4(x-2)-(5(2x+1)+5)=0

We multiply parentheses

10x-4x-(5(2x+1)+5)+8=0



We calculate terms in parentheses: -(5(2x+1)+5), so:

5(2x+1)+5

We multiply parentheses

10x+5+5

We add all the numbers together, and all the variables

10x+10

Back to the equation:

-(10x+10)



We add all the numbers together, and all the variables

6x-(10x+10)+8=0

We get rid of parentheses

6x-10x-10+8=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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