10x-22=(4x-8)+(2x+6)

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Solution for 10x-22=(4x-8)+(2x+6) equation: 



10x-22=(4x-8)+(2x+6)

We move all terms to the left:

10x-22-((4x-8)+(2x+6))=0



We calculate terms in parentheses: -((4x-8)+(2x+6)), so:

(4x-8)+(2x+6)

We get rid of parentheses

4x+2x-8+6

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

10x-6x+2-22=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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