10x-2(7x-6)+29=1/6(24x+54)

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Solution for 10x-2(7x-6)+29=1/6(24x+54) equation: 



10x-2(7x-6)+29=1/6(24x+54)

We move all terms to the left:

10x-2(7x-6)+29-(1/6(24x+54))=0



Domain of the equation: 6(24x+54))!=0

x∈R



We multiply parentheses

10x-14x-(1/6(24x+54))+12+29=0

We multiply all the terms by the denominator


10x*6(24x+54))-14x*6(24x+54))-(1+12*6(24x+54))+29*6(24x+54))=0

Wy multiply elements

360x^3(2+54))-(1+12*6(24x+54))+29*6(24x+54))=0

We do not support expression: x^3(2

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