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10x-15/2x-3=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
10x*2x-3*2x-15=0
Wy multiply elements
20x^2-6x-15=0
a = 20; b = -6; c = -15;
Δ = b2-4ac
Δ = -62-4·20·(-15)
Δ = 1236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1236}=\sqrt{4*309}=\sqrt{4}*\sqrt{309}=2\sqrt{309}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{309}}{2*20}=\frac{6-2\sqrt{309}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{309}}{2*20}=\frac{6+2\sqrt{309}}{40} $
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